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Simplify sendPLI. 

We use identical SSRC values on both sides, no need to map.
This commit is contained in:
Juliusz Chroboczek 2020-04-26 00:25:22 +02:00
parent c86b1c87d5
commit 78d3b7ab40
1 changed files with 5 additions and 17 deletions
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22
client.go
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@ -460,9 +460,9 @@ func rtcpListener(g *group, c *downConnection, s *webrtc.RTPSender) {
for _, p := range ps {
switch p := p.(type) {
case *rtcp.PictureLossIndication:
err := sendPli(g, s.Track(), c.remote)
err := sendPLI(c.remote, p.MediaSSRC)
if err != nil {
log.Printf("sendPli: %v", err)
log.Printf("sendPLI: %v", err)
}
case *rtcp.ReceiverEstimatedMaximumBitrate:
bitrate := uint32(math.MaxInt32)
@ -549,22 +549,10 @@ func updateBitrate(g *group, up *upConnection) (uint32, uint32) {
return audio, video
}
func sendPli(g *group, local *webrtc.Track, up *upConnection) error {
var track *webrtc.Track
for _, p := range up.pairs {
if p.local == local {
track = p.remote
break
}
}
if track == nil {
return errors.New("attempted to send PLI for unknown track")
}
func sendPLI(up *upConnection, ssrc uint32) error {
// we use equal SSRC values on both sides
return up.pc.WriteRTCP([]rtcp.Packet{
&rtcp.PictureLossIndication{MediaSSRC: track.SSRC()},
&rtcp.PictureLossIndication{MediaSSRC: ssrc},
})
}