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Simplify sendPLI.
We use identical SSRC values on both sides, no need to map.
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parent
c86b1c87d5
commit
78d3b7ab40
1 changed files with 5 additions and 17 deletions
22
client.go
22
client.go
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@ -460,9 +460,9 @@ func rtcpListener(g *group, c *downConnection, s *webrtc.RTPSender) {
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for _, p := range ps {
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switch p := p.(type) {
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case *rtcp.PictureLossIndication:
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err := sendPli(g, s.Track(), c.remote)
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err := sendPLI(c.remote, p.MediaSSRC)
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if err != nil {
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log.Printf("sendPli: %v", err)
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log.Printf("sendPLI: %v", err)
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}
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case *rtcp.ReceiverEstimatedMaximumBitrate:
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bitrate := uint32(math.MaxInt32)
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@ -549,22 +549,10 @@ func updateBitrate(g *group, up *upConnection) (uint32, uint32) {
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return audio, video
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}
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func sendPli(g *group, local *webrtc.Track, up *upConnection) error {
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var track *webrtc.Track
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for _, p := range up.pairs {
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if p.local == local {
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track = p.remote
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break
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}
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}
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if track == nil {
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return errors.New("attempted to send PLI for unknown track")
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}
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func sendPLI(up *upConnection, ssrc uint32) error {
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// we use equal SSRC values on both sides
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return up.pc.WriteRTCP([]rtcp.Packet{
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&rtcp.PictureLossIndication{MediaSSRC: track.SSRC()},
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&rtcp.PictureLossIndication{MediaSSRC: ssrc},
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})
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}
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